Question 1: Minimum Time to Synchronize Distributed Data
Developers at Amazon have deployed an application with a distributed database. The database is stored on total_servers
different servers numbered from 1 to total_servers
that are connected in a circular fashion, i.e., 1 is connected to 2, 2 is connected to 3, and so on until total_servers
connects back to 1.
A subset of servers is represented by an array servers
of size n
integers. These servers need to transfer data to each other to stay synchronized. Data transfer from one server to its direct neighbor takes 1 unit of time. Starting from any server, find the minimum amount of time required to transfer the data to all the other servers.
Example:
- Input:
total_servers = 8
n = 3
servers = [2, 6, 8]
Two possible paths are shown, but there can be many more:
- Path goes from 2 to 6 to 8, taking 6 units of time.
- Path goes from 2 to 8 to 6, taking 4 units of time.
Return the shorter path length, which is 4.
Function Description:
Complete the function getMinTime
in the editor below.
Parameters:
total_servers
(integer): The number of servers in the system.servers
(array of integers): The servers to share the data with.
Returns:
- Integer: The minimum time required to transfer the data on all the servers.
Constraints:
- The value of
total_servers
andn
satisfies:1 <= total_servers, n <= 1,000,000,000
.
Question 2: Sorting Points on the X-Axis
Developers at Amazon are working on a new sorting algorithm for points on the x-axis of the coordinate system.
There are n
points. The i-th
point initially has a weight of weight[i]
and is located at position i
on the x-axis. In a single operation, the i-th
point can be moved to the right by a distance of dist[i]
.
Objective:
Given weight
and dist
, find the minimum number of operations required to sort the points by their weights.
Example:
- Input:
n = 4
weight = [3, 6, 5, 1]
dist = [4, 3, 2, 1]
Explanation:
- Perform operation on point 1: Move it twice, increasing position by
2 * dist[0] = 8
. - Perform operation on point 2: Move it twice, increasing position by
2 * dist[1] = 6
. - Perform operation on point 3: Move it twice, increasing position by
2 * dist[2] = 4
.
Thus, the total number of operations required is 1 + 2 + 2 = 5
.
Function Description:
Complete the function getMinOperations
in the editor below.
Parameters:
weights
(array of integers): The weights of the points.dist
(array of integers): The distances the points can move.
Returns:
- Integer: The minimum number of operations required to sort the points.
Constraints:
- The number of points,
n
, satisfies:1 <= n <= 100,000
.
- Each weight and distance satisfies:
1 <= weights[i], dist[i] <= 1,000,000,000
.
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